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[求助] targets cone angle 是怎么使用的?

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发表于 2011-7-8 20:43:40 | 显示全部楼层 |阅读模式
哪位大哥 能和我说下' W1 y% U5 Q3 ]- ^
TFCalc targets cone angle是怎么使用的1 c9 B! s5 z! p0 o2 A! b% n
谢谢0 f- \2 O' r+ g  Q, }2 m4 @# j
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发表于 2011-7-8 21:16:51 | 显示全部楼层
本帖最后由 gds 于 2011-7-8 21:19 编辑
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6 m  w, P% f3 Y. K9 A  _$ r给你个官方的例子:  {" U/ [9 m# _6 c+ V6 J; S) b; s2 p
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Broadband AR for a Cone of Light ) [' W8 H; m; ]1 o- i9 }( D
Here we consider a coating on glass that reflects only 0.5% of a cone of light for a range of wavelengths from 420 to 680 nm. The cone axis is normal to the glass. The cone has an F-number of 0.778, which means the half-angle is 40 degrees. An uncoated glass surface reflects 4.4% of this cone of light. We use a feature new to version 3.5: cone-angle targets. As optimization targets we use . N( _' ^8 A& T3 z
R < 0.5% for wavelengths 420, 425, 430,..., 680 and for a 40-degree cone
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% I) s$ f- l4 R! BIn TFCalc, these targets are easy to enter by using the "Generate Cone Targets" command on the Options menu of the "Targets - Cone Angle" window. We use TFCalc's needle/tunneling optimization to design the coating from "scratch". That is, we begin the design process with a single thin layer of TiO2 and allow TFCalc to increase the thickness and number of layers in the design. TFCalc finds a 6-layer design in a few minutes. The performance of this design is shown below. The little circles indicate the optimization targets.8 s$ s1 v2 h- V7 L) e2 N

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' p7 }; ~" S! r' G7 b2 p4 V Here is the design, starting with the layer closest to glass, and with thicknesses given in nm:
8 m) J" d8 R+ {  nTIO2          11.04
/ m0 z' d. c4 L) J* n3 A7 J- zSIO2          44.433 c! {. }7 [- _
TIO2          34.991 {/ ^6 q: [2 k: V& J( [
SIO2          28.25
& z# S9 ]& M- G& K4 s. |* TTIO2          30.46; t2 b/ v8 d$ S, T3 E
SIO2         104.92& Q- y- g' R6 r3 N
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发表于 2012-9-7 10:35:36 | 显示全部楼层
多角度的?还是圆锥角啊?
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