targets cone angle 是怎么使用的？

cai004

哪位大哥 能和我说下
6 G# i! }3 q. \* A" A8 ]4 v4 OTFCalc targets cone angle是怎么使用的
谢谢
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gds

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给你个官方的例子：


0 z! `! _. Z% w) b2 nBroadband AR for a Cone of Light
$ B- O  a  P! J$ i1 `Here we consider a coating on glass that reflects only 0.5% of a cone of light for a range of wavelengths from 420 to 680 nm. The cone axis is normal to the glass. The cone has an F-number of 0.778, which means the half-angle is 40 degrees. An uncoated glass surface reflects 4.4% of this cone of light. We use a feature new to version 3.5: cone-angle targets. As optimization targets we use
R < 0.5% for wavelengths 420, 425, 430,..., 680 and for a 40-degree cone
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% d9 N- n; [/ |4 B5 h  m! YIn TFCalc, these targets are easy to enter by using the "Generate Cone Targets" command on the Options menu of the "Targets - Cone Angle" window. We use TFCalc's needle/tunneling optimization to design the coating from "scratch". That is, we begin the design process with a single thin layer of TiO2 and allow TFCalc to increase the thickness and number of layers in the design. TFCalc finds a 6-layer design in a few minutes. The performance of this design is shown below. The little circles indicate the optimization targets.
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; w7 {* ?, l7 Z6 q. M Here is the design, starting with the layer closest to glass, and with thicknesses given in nm:
TIO2          11.04
SIO2          44.43
TIO2          34.99
  a, |9 c/ ?6 D/ P( aSIO2          28.25
TIO2          30.46
SIO2         104.92
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280870377

多角度的？还是圆锥角啊？