targets cone angle 是怎么使用的？

cai004

哪位大哥 能和我说下
8 O+ b" l7 k$ `0 |$ i  I2 j* c, GTFCalc targets cone angle是怎么使用的
谢谢
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gds

; S+ g* _! \/ Y. ]  e给你个官方的例子：
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Broadband AR for a Cone of Light
Here we consider a coating on glass that reflects only 0.5% of a cone of light for a range of wavelengths from 420 to 680 nm. The cone axis is normal to the glass. The cone has an F-number of 0.778, which means the half-angle is 40 degrees. An uncoated glass surface reflects 4.4% of this cone of light. We use a feature new to version 3.5: cone-angle targets. As optimization targets we use
R < 0.5% for wavelengths 420, 425, 430,..., 680 and for a 40-degree cone

5 l* l7 L# C  k" ^5 j# j3 {# _In TFCalc, these targets are easy to enter by using the "Generate Cone Targets" command on the Options menu of the "Targets - Cone Angle" window. We use TFCalc's needle/tunneling optimization to design the coating from "scratch". That is, we begin the design process with a single thin layer of TiO2 and allow TFCalc to increase the thickness and number of layers in the design. TFCalc finds a 6-layer design in a few minutes. The performance of this design is shown below. The little circles indicate the optimization targets.
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Here is the design, starting with the layer closest to glass, and with thicknesses given in nm:
TIO2          11.04
! M( ?& V. A( @) W7 ~5 a/ B1 S. qSIO2          44.43
  {- i& _6 p& y; w7 E  p3 |7 a  x7 TTIO2          34.99
SIO2          28.25
TIO2          30.46
SIO2         104.92
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280870377

多角度的？还是圆锥角啊？